![]() In the video Sal operates y=2*log2(-(x+3) however, if we applied the rules of transformation to 2*log2(-x-3) we would have very different coordinates of the graph. Hope this is a little more satisfying to you. Then at (-3,-2), you would still move to get to (-2,-2), but instead of, it would move (notice in both cases, you just multiplied the y value by 2) to get to (-3+10, -2+2) or (7,0). With a shift down 2 and a multiplier of 2 (vertical stretch). This gives a vertical asymptote at x=-3 which is the start. Given the function of Adrianna f(x)=2 log(x+3)-2, the transformations to the parent function would include a vertical stretch and a shift of (0,0) to (-3,-2) which you then act as if it is (0,0) even though it really is not. With the parent function, you would draw the horizontal asymptote at x=0, plot the points (1,0) and (10,1) and draw a rough curve. C are translations to the left and right, and d shifts up and down. A is a vertical stretch or compression as well as reflect across x if negative, b is a horizontal stretch or compression as well as having a negative reflect across y. Next, you need to know your transformations which are relative to all functions f(x) = a f(bx+c)+d. With a lot of graphs, you will not even be able to reach the (10,1) point if you are moving it around. It has a vertical asymptote at x=0, goes through points (1,0) and (10,1). You first need to understand what the parent log function looks like which is y=log (x). ![]() ![]() Log functions do not have many easy points to graph, so log functions are easier to sketch (rough graph) tban to actually graph them. ![]()
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